1·This sample formula allows any application to hold twice the average number of locks.
该样本公式允许任何应用程序持有的锁是平均数的两倍。
2·Also, observe the average number of connections created and destroyed.
同时,观察已创建和已毁坏连接的平均数。
3·The pool is not large enough to serve the workload, if average number of active threads is constantly close to maximum size of the pool.
如果活动线程的平均数时常接近线程池的最大大小,这说明该线程池太小,不足以满足工作量。
4·The average number of daily transactions per user was 5303.
每个用户每天事务的平均数为5303个。
5·In addition to considering the requirements of the average number of Concurrent users, the complexity of your application also influences the resources required.
除了考虑Concurrent用户平均数的需求外,您的应用程序的复杂性也会影响资源需求。